Which of the following are wise entrepreneurial decisions or concepts? Check all of the boxes that apply.

In C++ please (read the image below for instructions)

FromTheMoon [43]

Using the knowledge in computational language in C code it is possible to write a code that print the month name along with their rainfall inches. Then we have to calculate the total rainfall.

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// function to print the rainfall of each month

void rainfallStatistics(string month[], double rainfall[]){

double sum = 0; // variable to store the total sum of rainfall

string maxMonth = month[0]; // variable to return month with maximum rainfall

double maxRainfall = INT_MIN; // variable to store the maximum rainfall

// running the loop till the last month

for(int i=0; i<12; i++){

// printing the month and rainfall

cout<< month[i] << " " << fixed << setprecision(2) << rainfall[i] << " inches" << endl;

// storing the sum

sum = sum + rainfall[i];

// checking the month with highest rainfall

if(rainfall[i] > maxRainfall){

maxRainfall = rainfall[i];

maxMonth = month[i];

}

// calculating the average of the rainfall

double average = sum / double(12);

cout << endl;

cout << "Total for the year " << sum << " inches" << endl;

cout << "Average rainfall per month " << average << " inches" << endl;

cout << "Month with the greatest rainfall was " << maxMonth << " with rainfall of " << maxRainfall << " inches" << endl;

}

// driver program

int main()

{

// array to store the nonth name

string month[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

// array to store the rainfall

double rainfall1[12] = { 4.50, 4.25, 3.26, 1.35, 0.80, 0.20, 0.10, 0.00, 0.40, 1.20, 2.96, 4.71 };

double rainfall2[12] = { 3.50, 1.25, 7.26, 8.35, 2.80, 0.00, 1.10, 4.00, 9.40, 2.20, 3.96, 4.71 };

cout << "Hayward Statistics" << endl;

cout << endl;

cout<< "Month" << " " << "Rainfall" << endl;

// calling the function for Hayward

rainfallStatistics(month, rainfall1);

cout << endl;

cout << "Houston Statistics" << endl;

cout << endl;

cout<< "Month" << " " << "Rainfall" << endl;

// calling the function for Houston

rainfallStatistics(month, rainfall2);

return 0;

}

See more about c code at brainly.com/question/19705654

#SPJ1

8 0

2 years ago

Adios brainly, you were sh.t sometimes, but you had your moments, wont be posting that much take my points away i d c

svlad2 [7]

you got a bad day today, bud?

3 0

3 years ago

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Given that note, write a program which tells us the major scale starting at that note, using the pattern above. In the main bloc

White raven [17]

Solution and Explanation:

the_notes = ['C','C#','D','D#','E','F','F#','G','G#','A','A#','B'] #original list

def get_scale(choice): #function to get the major diatonic scale

steps=[1,1,.5,1,1,1,.5] #separate list for steps

size=None

for i in range(0,12): #loop to find out the index of the note entered

if(the_notes[i]==choice):

size =i

break

new_notes=the_notes[size:] + the_notes[:size]

#the above statement rotate the list so that the entered note can become the first note in the new list(i.e new notes)

index =0 #

scale="" #a string to store the major diatonic scale

for i in range(0,7):

scale+=new_notes[index]+" "

if(steps[i]==1):

index = index+2

else:

index=index+1

return scale

#main block

while(1):

choice=input("What scale do you want or Q to quit? ")

if(choice=='Q'):

break

elif(choice in the_notes):

print(get_scale(choice))

else:

print("That is not a note")

5 0

3 years ago

Students who interact online with others from different cultures should remember that

aliya0001 [1]

Answer:

they are dealing with people, not computers.

8 0

4 years ago

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Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integer

Xelga [282]

Answer:

import java.util.Scanner;

public class ListOfIntegers {

public static void main(String[] args) {

// Create an object of the Scanner class to allow for user input

Scanner input = new Scanner(System.in);

// Prompt the user for the number of integers they want to enter

System.out.print("Enter the number of integers : ");

// Get and store the number of integers entered by user

int n = input.nextInt();

System.out.println();

// Create an array to hold the integers

// The array has the same length as the number of integers

int[] numbers = new int[n];

// Create a loop that asks the user to enter all integers

// At each cycle of the loop, save the entered integer into the array

for (int i = 0; i < n; i++) {

System.out.print("Enter number " + (i + 1) + " : ");

numbers[i] = input.nextInt();

System.out.println();

}

// Prompt the user for the lower bound

System.out.print("Enter the lower bound : ");

// Get and store the lower bound in a variable

int lowerbound = input.nextInt();

System.out.println();

// Prompt the user for the upper bound

System.out.print("Enter the upper bound : ");

// Get and store the upper bound in a variable

int upperbound = input.nextInt();

System.out.println();

System.out.println("OUTPUT :: ");

// Create a loop to cycle through the array of numbers.

// At each cycle, check if the array element is within range.

// If it is within range, print it to the console

for (int j = 0; j < numbers.length; j++) {

if (numbers[j] >= lowerbound && numbers[j] <= upperbound) {

System.out.print(numbers[j] + " ");

}

Explanation:

Please go through the comments in the code for more readability and understanding. The source code file has been attached to this response. Kindly download the file to get a better formatting of the code.

Hope this helps!

Download java

7 0

4 years ago

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