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Nady [450]
3 years ago
11

What is the solution to the quadratic inequality?

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0
<h2><em><u>Answer:</u></em></h2><h2><em><u>First, solve each inequality. I'll solve the first one first. </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>7 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>5 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>12 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Therefore, x could be any number less than or equal to 6. In interval notation, this looks like: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>] </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>The parenthesis means that the lower end is not a solution, but every number above it is. (In this case, the lower end is infinity, so a parenthesis must be used, since infinity is not a real number and so it cannot be a solution.) The bracket means that the upper end is a solution. In this case, it indicates that not only could  </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> be any number less than 6, but it could also be 6. </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Let's try the second example: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>4 </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>4 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>16 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>18 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Therefore, x could be any number greater than 6, but x couldn't be 6, since that would make the two sides of the inequality equal. In interval notation, this looks like: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>The parentheses mean that neither end of this range is included in the solution set. In this case, it indicates that neither 6 nor infinity are solutions, but every number in between 6 and infinity is a solution (that is, every real number greater than 6 is a solution). </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Now, the problem used the word "OR", meaning that either of these equations could be true. That means that either  </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is on the interval  </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>] </u></em></h2><h2><em><u> or the interval  </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u>. In other words,  </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is either less than or equal to 6, or it is greater than 6. When you combine these two statements, it becomes clear that  </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> could be any real number, since no matter what number  </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is, it will fall in one of these intervals. The interval "all real numbers" is written like this: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Final Answer</u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2>

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Can somebody step by step explain how to solve this problem??<br><br> (3x^2y)(-7xy^3)
charle [14.2K]

Answer:

\boxed{\bold{-21x^3y^4}}

Explanation:

[ Step One ] Remove Parenthesis: (a) = a

\bold{-3x^2y\cdot \:7xy^3}

[ Step Two ] Multiply: \bold{3\cdot \:7=21}

\bold{-21x^2xy^3y}

[ Step Three ] Apply Exponent Rule \bold{\:a^b\cdot \:a^c=a^{b+c}: \ x^2x=\:x^{2+1}=\:x^3}

\bold{-21x^3y^3y}

[ Step Four ] Apply Exponent Rule: \bold{y^3y=\:y^{1+3}=\:y^4}

\bold{-21x^3y^4}

[ \boxed{\bold{Final \ Answer}} ]

➤ \bold{-21x^3y^4}

\boxed{\bold{Mordancy}}

5 0
3 years ago
Read 2 more answers
Two cylinders are similar. The surface area of one is 49 cm ^ 2 , and the surface area of the other is 121 cm ^ 2 . Find the sca
dalvyx [7]

Answer:

7 : 17.29

Step-by-step explanation:

==>Given:

Two similar cylinders:

Surface area of Cylinder A = 49cm²

Surface area of Cylinder B = 121cm²

==>Required:

Scale factor between both cylinders

==>Solution:

We can easily get the scale factor between both by taking the following steps:

=>Set up a ratio of their surface area:

Smaller cone surface area : larger cone surface area

49:121

= 49/121

=>Simplify the ratio gotten:

Dividing the denominator and the numerator by 7, would give us,

7/17.29

= 7:17.29

8 0
3 years ago
Read 2 more answers
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