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Zielflug [23.3K]
3 years ago
12

What is the value of x? (Use only the digits 0 - 9 and the decimal point, if needed, to write the value.)

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

Step-by-step explanation:

More information is needed to answer this question.

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HELP FAST I JUST NEED ANSWER
lukranit [14]

Answer:

449.60 or yellow

Step-by-step explanation:

5 0
3 years ago
Square root of -1? PLEASE HELP
kolezko [41]

My understanding it would be letter ( i )  because it is imaginary.  

7 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The groundhog population of​ Punxsutawny, Pennsylvania is closely monitored each year. Two years ago the population decreased by
kap26 [50]

Answer:

There was a increase of 1.7% over these three​ years

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: \frac{100-a}{100}

For a increase of a%, we multiply by: \frac{100+a}{100}

What was the percentage​ increase/decrease of groundhogs over these three​ years?

Decrease of 12%(multiplication by 0.88).

Increase of 6%(multiplication by 1.06).

Increase of 9%(multiplication by 1.09).

After these three years:

0.88*1.06*1.09 = 1.017

1.017 - 1 = 0.017

0.017*100% = 1.7%

There was a increase of 1.7% over these three​ years

3 0
3 years ago
I’ll give you all my love and affection if you help me with this ASAP PLEASE ;)
guapka [62]
Answer: (12,0)


Steps:

First, put the equation in slope-intercept form.

y=mx+b

1.5x + 4.5y =18

Subtract 1.5x from both sides.

4.5y =-1.5x +18

Divide both sides by 4.5 to isolate y.

y = -1/3x + 4


Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.

0 = -1/3x + 4

Subtract 4 from both sides

-4 = -1/3x

Divide both sides by -1/3 to isolate the x

12=x
4 0
3 years ago
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