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Zielflug [23.3K]
2 years ago
12

What is the value of x? (Use only the digits 0 - 9 and the decimal point, if needed, to write the value.)

Mathematics
1 answer:
Serga [27]2 years ago
4 0

Answer:

Step-by-step explanation:

More information is needed to answer this question.

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15 is A, 22+X=8
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3+3+7+8+5+4+33yx11+<br><br><br> COME on People easy math for 30points.
Paraphin [41]

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363y + 30

Step-by-step explanation:

3 0
3 years ago
5 customers buy 10,15,20,25,30 toffees respectively from 1 shop. But the the person who bought 20 toffees forgot to pay .if the
Mice21 [21]

Answer:

40% profit

Step by step Explanation:

Profit percentage

=( profit/cost price) * 100

0.2 = profit/cost

10+15+20+25+30= 100

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Cost price total= $100

Profit made when buyer of 20 toffe didn't say was

0.2=profit/cost

0.2*100 =$20

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Total profit = $40

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3 years ago
Which polygon in the diagram cannot be mapped onto the others by similarity transformations?
Rom4ik [11]

Answer:   B.) PQRST


Step-by-step explanation:

There are no options but if its the same question I just had on a test then this is the answer..

Hope this helps..

6 0
3 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

8 0
3 years ago
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