Answer: Answer: x≥ −1
/2
Step-by-step explanation:
You're looking for values to factor this equation into (x+p)(x+q)
such that pq=12 and p+q=b
Assuming we're looking for simple values, you can start by factorizing 12:
12 = 3*4 = 2*6 = 12*1 = -3*-4 = -2*-6 = -12*-1
For 3 and 4, b would be 7
2 and 6 => b=8
12 and 1 => b=13
and for the negatives
b can be -7, -8 or -13
So the total set is -13, -8, -7, 7, 8, 13
Answer:
b11 = -14
b12 = 9
b13 = 8
Step-by-step explanation:
* Lets revise some notes to solve the problem
- Any matrix has a dimension m × n, where m is the number of rows
and n the number of columns
- We can add matrices with same dimensions
* Now lets solve the problem
∵ ![B+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]](https://tex.z-dn.net/?f=B%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D15%26-7%264%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%2612%5C%5C4%260%262%5Cend%7Barray%7D%5Cright%5D)
- Let ![B=\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%26b13%5C%5Cb21%26b22%26b23%5Cend%7Barray%7D%5Cright%5D)
∴ ![\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%26b13%5C%5Cb21%26b22%26b23%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D15%26-7%264%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%2612%5C%5C4%260%262%5Cend%7Barray%7D%5Cright%5D)
- Lets add and find the missing
* Lets start with the first rows
∵ b11 + 15 = 1 ⇒ subtract 15 from both sides
∴ b11 = -14
∵ b12 + -7 = 2 ⇒ add 7 to both sides
∴ b12 = 9
∵ b13 + 4 = 12 ⇒ subtract 4 from both sides
∴ b13 = 8
* Now lets start with the second rows
∵ b21 + 0 = 4
∴ b21 = 4 ⇒ given
∵ b22 + 1 = 0 ⇒ subtract 1 from both sides
∴ b22 = -1 ⇒ given
∵ b23 + 2 = 2 ⇒ subtract 2 from both sides
∴ b23 = 0 ⇒ given
Answer:
The equation of the line that goes through points (1,1) and (3,7) is 
Step-by-step explanation:
Determine the equation of the line that goes through points (1,1) and (3,7)
We can write the equation of line in slope-intercept form
where m is slope and b is y-intercept.
We need to find slope and y-intercept.
Finding Slope
Slope can be found using formula: 
We have 
Putting values and finding slope

We get Slope = 3
Finding y-intercept
y-intercept can be found using point (1,1) and slope m = 3

We get y-intercept b = -2
So, equation of line having slope m=3 and y-intercept b = -2 is:

The equation of the line that goes through points (1,1) and (3,7) is 