Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required data are not given.
I will use the following data as an illustration of how to calculate median and range.
We have:

<u>Calculate range</u>
Identify the highest and the least


So, the range is:



<u>Calculate the median</u>
The number of data we are using is 6 (i.e. even).
So, the position of the median item is:




A decimal result implies that the median is the mean of the integer values before and after the result.
In this case, the median is the mean of the item at 3rd and 4th positions.
So:



Answer: 29 feet (deepest) at 6 am
21 feet (shallowest) at Midnight & Noon
<u>Step-by-step explanation:</u>
y = -4 cos (π/6)t +25
Amplitude (A) = 4
-A means it is a reflection over the x-axis (starts at minimum)<em> </em>
Period = 2π/B → Period = 12
Phase shift = C/B → Phase Shift = 0
Midline (D) = 25
Midline (D) ± Amplitude (A) = Max & Min
Max: 25 + 4 = 29
Min: 25 - 4 = 21
Change the coordinates of y = cos (x) as follows:
- x-value: Add C then divide by B
- y-value: Multiply by A then add D
Note that the equation shows: A = -4, B = π/6, C = 0, D = 25

<em>Answer:</em>
<em>8:6</em>
<em>Hope it helped. :)</em>
<em />
Answer:
Kindly check explanation
Step-by-step explanation:
Calculate the 25th, 50th, and 75th percentiles.
b. Calculate the interquartile range.
c. Construct a boxplot. Are there any outliers?
Reordered data:
25, 40, 52, 55, 60, 70, 70, 72, 74, 75, 75, 80, 80, 85, 85, 86, 87, 90, 92, 99
25 th percentile :
1/4 (n + 1)th, tetm
n = 20
1/4(21) = 5.25th term
(5 + 6) th term / 2
= 65
50th percentile :
1/2 (n + 1)th, tetm
n = 20
1/2(21) = 10.5th term
(10 + 11) th term / 2
= 75
75th percentile:
3/4 (n + 1)th, tetm
n = 20
3/4(21) = 15.75th term
(15 + 16) th term / 2
= 85.5
Interquartile range :
Q3 - Q1
75th percentile - 25th percentile
85.5 - 65
= 20.5
25 is an Outlier