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3 years ago

What is the fourth term in this multiplication pattern ?

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

2 * 6^(n-1)
a(sub4) = 2 * 6^(4-1)
a(sub4) = 2 * 6^3
a(sub4) = 2 * 216
a(sub4) = 432

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Find the perimeter of the quadrilateral.

levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

$4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches$

The values of the side lengths when x = 2 are

$(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch$

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=12%5Ctimes%2012%5Ctimes%2011" id="TexFormula1" title="12\times 12\times 11" alt="12\times 12\t

vekshin1

12 x 12 x 11
12 x 12 = 144
144 x 11 = 1584

the answer is 1584 ! hope that helps :)

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3 years ago

a value of 500 increases by 12%. Write and equation that could be used to find the new value. What is the new value?

myrzilka [38]

500×12%
(500×12)÷100
6000÷100
=60

so,
500+60=560

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shutvik [7]

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