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3 years ago

What is the fourth term in this multiplication pattern ?

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

2 * 6^(n-1)
a(sub4) = 2 * 6^(4-1)
a(sub4) = 2 * 6^3
a(sub4) = 2 * 216
a(sub4) = 432

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Determine the coordinates of the image of D(4, −3) under the following translations.

Maru [420]

Answer:

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2 years ago

the area of a square garden is 267 ft^2 what is the side length of each side? round your answer to the nearest hundredth place.

aksik [14]

Answer:

Side Length=16.34 ft
No

Step-by-step explanation:

The area of the square garden= $267$ ft^2$

Area of a Square of Side length s $=s^2$

Therefore:

$s^2=267$ ft^2\\$Take the square root of both sides\\s=\sqrt{267} \\$Side Lenght, s=16.34 ft (to the nearest hundredth place)$

Perimeter

Perimeter of a Square of Side length s=4s

Therefore, the perimeter of the garden =4*16.34=65.36 ft

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2 years ago

If dm=35 what is the value of r?

Ksju [112]

Answer:

The answer is 11

Step-by-step explanation:

The answer is 11 if you have PQSR as the diagram and

(3x-6) degrees & (x+2) degrees in the diagram.

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3 0

2 years ago

What is 40 percent of 35

Murrr4er [49]

Hey there!

You can figure this out by making 40% into a decimal. This decimal would be .4. So multiply 35 by .4. You get 14. So 14 is 40 percent of 35.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv

erma4kov [3.2K]

Answer:

$P_2 = \$6,000\\P_1 = \$14,000$

Step-by-step explanation:

The formula of simple interest is:

$I = P_0rt$

Where I is the interest earned after t years

r is the interest rate

$P_0$ is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

For the first account r = 0.07 per year.

Then the formula is:

$I_1 = P_1r_1t$

Where

$P_1$ is the initial amount in account 1 at a rate $r_1$ during t = 1 year

$I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1$

For the second account r = 0.05 per year.

Then the formula is:

$I_2 = P_2r_2t$

Where

$P_2$ is the initial amount in account 2 at a rate $r_2$ during t = 1 year

Then

$I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2$

We know that the final profit was I $1,280.

$I = I_1 + I_2=1,280$

Substituting the values $I_1$ , $I_2$ and I we have:

$1,280 = 0.07P_1 + 0.05P_2$

As the total amount that was invested was $20,000 then

$P_0 = P_1 + P_2 = 20,000$

Then we multiply the second equation by -0.07 and add it to the first equation:

$0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------$

$-0.02P_2 = -120\\\\P_2 = 6,000$

Then $P_1 = 14,000$

4 0

3 years ago