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2 years ago

What is the fourth term in this multiplication pattern ?

Mathematics

1 answer:

vova2212 [387]2 years ago

4 0

2 * 6^(n-1)
a(sub4) = 2 * 6^(4-1)
a(sub4) = 2 * 6^3
a(sub4) = 2 * 216
a(sub4) = 432

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The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take

Alex73 [517]

Answer:

It will take 80 days for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = $1\frac{2}{5}=\frac{7}{5}$

= $1.4\ kilograms.$

Thus, the time required = $\frac{required\ weight}{rate\ of\ weight}$

= $\frac{112}{1.4}$

= $80.$

The time required = 80 days.

Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.

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2 years ago

In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are

Vitek1552 [10]

1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that:

- The number of charter schools is 4 less than twice the number of alternative schools.
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2. So, you have:

x=2y-4 (i)

x=48 (ii)

3. Then, when you substitute x=48 into the equation (i), you obtain:

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4. Now, you must clear "y, as below:

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The answer is: There are 26 alternative schools.

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