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Mamont248 [21]
3 years ago
8

How many times does the quadratic function below intersect the x-axis? y=x+10x+25

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

It touches the x-axis once, but does not intersect it

Step-by-step explanation:

I'm assuming it's supposed to be y = x² + 10x + 25.  This equation does not intersect the x-axis, but it does touch the x-axis.  

Solve the equation for x...

0 = x² + 10x + 25

factor...

0 = (x + 5)(x + 5)

The solution repeats, this means that the function touches the x-axis and then bounces off, but doesn't intersect it.  Intersect meant to cross the line, here it just touches it.

See the attached photo to see the graph...

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A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
3 years ago
PLEASE HELP!!!<br> I don't know how to do this...<br> (screenshots provided)
Mrac [35]

Answer:

i really dont know how to do this and i dont think anybody here knows how to

Step-by-step explanation:

4 0
3 years ago
Factor the following Polynomials<br> 9x^2 - 42x + 49
Allisa [31]

Answer:(3x-7) (3x-7)

Step-by-step explanation:

9x2-42x+49

The two by the 9 is power of 2 so the small two above

6 0
4 years ago
Anyone who plays or watches sports has heard of the "home field advantage." Teams tend to win more often when they play at home.
AveGali [126]

Answer:

H0 : μ = 0.5

H0 : μ > 0.5

Kindly check explanation

Step-by-step explanation:

H0 : μ = 0.5

H0 : μ > 0.5

We perform a right tailed test :

Sample proportion :

Number of games won, x = 142

Number of games, n = 250

phat = x / n = 142 / 250 = 0.568 = 56.8%

Yes, it is consistent

Test statistic :

(phat - p) * √Phat(1-Phat)/n

1 -Phat = 1 -0.568 = 0.432

(0.568 - 0.5) /√(0.568*0.432)/250

0.068 / 0.0313289

= 2.17

The Pvalue using the z test statistic :

Pvalue = 0.015

α = 0.03

Since ;

Pvalue < α ; We reject the null and conclude that teams tend to win more often when they play at home.

8 0
3 years ago
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lbvjy [14]

Answer:

I think it's B

Step-by-step explanation:

4 0
3 years ago
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