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Mamont248 [21]
3 years ago
8

How many times does the quadratic function below intersect the x-axis? y=x+10x+25

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

It touches the x-axis once, but does not intersect it

Step-by-step explanation:

I'm assuming it's supposed to be y = x² + 10x + 25.  This equation does not intersect the x-axis, but it does touch the x-axis.  

Solve the equation for x...

0 = x² + 10x + 25

factor...

0 = (x + 5)(x + 5)

The solution repeats, this means that the function touches the x-axis and then bounces off, but doesn't intersect it.  Intersect meant to cross the line, here it just touches it.

See the attached photo to see the graph...

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What is the answer to this question plss and thank you
cluponka [151]

A defines the function

f(1) = - 8 ×( \frac{5}{2} )^{0} = - 8 × 1 = -8

f(2) = - 8 ×( \frac{5}{2}) ^{1} = - \frac{(8.5)}{2}= - 20

f(3) = - 8 ×( \frac{5}{2}) ^{2} = - 8 × \frac{25}{4} = - 50

f(4)= - 8 ×( \frac{5}{2}) ^{3} = - 8 × \frac{125}{8} = -125

f(5) = - 8 ×( \frac{5}{2}) ^{4} = - 8 × \frac{625}{16} = - \frac{625}{2}




4 0
3 years ago
Please help me!!!!!!!!!!!!!!!!!
svetlana [45]

Answer:

10

Step-by-step explanation:

5 0
3 years ago
I really need help on themis math!!!!!!!!!!
cluponka [151]
Midpoint formula is M=( (x1+x²)/2 , (y1+y²)/2 )
let A be there point (x1,y1), our (2,3)

plug into the formula to get

(-2,1)=( (2+x²)/2, (3+y2)/2 )
so -2=(2+x2)/2 and 1=(3+y2)/2



x2=-6 and y2=-1
answer is B

7 0
3 years ago
What is the equation of the line that has a slope of 0 and passes through the point (6,-8)
Fofino [41]

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=0(x-6)\implies y+8=0\implies y=-8

5 0
3 years ago
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Suppose X and Y represent two different school populations where X > Y and X and Y must be greater than 0. Which of the follo
Stells [14]

Answer:(X+Y)²

X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.

X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.

(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:

X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².

7 0
3 years ago
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