Question

A square pyramid has a base length of 4 inches. The height of each triangular face is 12 inches. What is the surface area of the pyramid?

Answer 1

Answer:

The surface area of the given pyramid is 112 $inches^{2}$.

Step-by-step explanation:

Base length of the pyramid = 4 inches

Area of the base = $length^{2}$

                            = $4^{2}$

                            = 16

Area of its base = 16 $inches^{2}$

Area of one of its triangular surface = $\frac{1}{2}$ x base x height

                                 = $\frac{1}{2}$ x 4 x 12

                                 = 2 x 12

                                 = 24 $inches^{2}$

Area of all its four triangular surfaces = 4 x 24

                                                       = 96 $inches^{2}$

surface area of the pyramid = sum of areas of all its surfaces

                                               = 16 + 96

                                       = 112 $inches^{2}$

The surface area of the given pyramid is 112 $inches^{2}$.