Answer:
Its A buddy
Explanation:
that what it was on ingenuity
Answer:
so what is this uhhhhhhhhhh
More info please, it is very invalid
Answer:
<em>This program is written in C++</em>
<em>Comment are used to explain difficult lines</em>
<em>The first program that prints 0 to 20 (in decimal) starts here</em>
#include<iostream>
int main()
{
//Print From 0 to 20
for(int i = 0;i<21;i++)
{
std::cout<<i<<'\n';
}
}
<em>The modified program to print 0 to 20 in hexadecimal starts here</em>
#include<iostream>
using namespace std;
int main()
{
//Declare variables to use in conversion;
int tempvar, i=1,remain;
//Declare a char array of length 50 to hold result
char result[50];
//Print 0
cout<<"0"<<endl;
// Iterate from 1 to 20
for(int digit = 1; digit<21; digit++)
{
//Start Conversion Process
//Initialize tempvar to digit (1 to 20)
tempvar = digit;
while(tempvar!=0)
{
//Divide tempvar by 16 and get remainder
remain = tempvar%16;
if(remain<10)
{
result[i++]=remain + 48;
}
else
{
result[i++] = remain + 55;
}
//Get new value of tempvar by dividing it by 16
tempvar/=16;
}
//Print result
for(int l=i-1;l>0;l--)
{
cout<<result[l];
}
i=1;
cout<<endl;
}
return 0;
}
//The Program Ends Here
See Attachments for program 1 and 2; program 2 is the modified version of 1
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
cpp
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
cpp
</span>
Answer:
True
Explanation:
In Computer science, It's true that injection attacks variants can occur whenever one program invokes the services of another program, service, or function and passes to it externally sourced, potentially untrusted information without sufficient inspection and validation of it.
