Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above
32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
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He could use bold or bigger text just a suggestion.
Answer:
<=
Explanation:
Pretty much the same as in maths