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Temka [501]
3 years ago
15

Evaluate 105*95 using identities

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

9975

Step-by-step explanation:

See attachment.

( 105 ) * ( 95 )

(100+5) * (100-5)

100*100 * (1 + 5/100) * ( 1 - 5/100)

10000 * ( 1 - 5/100 + 5/100 - {25/10000} )

- 5/100 + 5/100, they cancel each other out to 0

10000 * ( 1 + 0 - {25/10000} )

10000 * ( 1 - {25/10000} )

10000 - {25*10000/10000}

10000 - {25}

9975

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5. Consider the diagram below. Choose the correct statement."
Ivanshal [37]

Answer:

Option (3)

Step-by-step explanation:

Option (1).

AB and SE are coplanar.

Incorrect.

AB lies in a plane ABS and SE lies in another plane SEL.

Option (2).

TS and SE intersect at E.

Incorrect.

They intersect at S.

Option (3).

R intersects K at SB.

Correct.

Since line of intersection of planes R and K is SB

Option (4)

AB and BL are perpendicular at B.

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6 0
4 years ago
Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1<br>​
slamgirl [31]

Answer:Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1

Step-by-step explanation:

3 0
3 years ago
Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9
a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is x^2+4x-21=0. We need to find the solution of this equation.

If the equation is in the form of ax^2+bx+c=0, then its solutions are given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7

So, the solutions of the quadratic equation are 3 and -7.      

6 0
3 years ago
Correct and best explained answer gets brainliest.
Oduvanchick [21]
The answer is b. okay
4 0
3 years ago
5. Given: BCDF is a parallelogram; line AB is congruent to line BF
solong [7]
A and E are corresponding angles so A=E
3 0
2 years ago
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