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2 years ago

How many times greater is the product 4x300 than the product 4x30?

Mathematics

2 answers:

Anna71 [15]2 years ago

8 0

1200 and120
1200-120=1080

Dvinal [7]2 years ago

8 0

120 more than 1200 and also it mor than 4 × 30

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KonstantinChe [14]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Read 2 more answers

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A What is the value of the A^2?

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

Bill had $5.42 and earned 2.25 he spent $3.78 how much did he have left

inna [77]

Answer:

3.89

Step-by-step explanation:

5.42+2.25=7.67

7.67-3.78=3.89

Hope this helps

8 0

3 years ago

PLEASE HELP !!!!!!! Jordan got a new money bank for his birthday with $20 inside. He puts part of his weekly allowance in his ba

kupik [55]

Answer:

Slope of the function is $=3.75$ ,Y-intercept $=20$ .

The function is $y=3.75(x)+20$ with initial value $=20$ ,Jordan puts $\$3.75$ each week andthe amount saved by Jordan after $52$ week $=215\$$ .

Step-by-step explanation:

To understand the slope and y-intercept lets assign $x$ as number of weeks and $y$ as the money saved by Jordan.

Jordan is already having a sum of $\$20$ inside the money bank so in $0$ week the amount is $\$20$ can be written as $(x,y) =(0,20)$ in coordinate form.

SImilarly

We have $(x,y) =(0,20)$ and $(x_1,y_1) =(25,113.75)$

Part A:

The function is $y=m(x)+b$

From point-slope form,we have slope (m)

and $m=\frac{y_1-y}{x_1-x}$ ,plugging the values of the points.

$m=\frac{113.75-20}{25-0}=3.75$

Y-intercept of this function is the constant term or the money of $\$20$ that is already inside the money bank.

We can also calculate y-intercept by arranging the function as $b=y-m(x)$ choosing any $(x_1,y_1) = (25,113.75)$ coordinate and here $b$ is the y-intercept.