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Answer: g=5
Step-by-step explanation:
Answer:
x = -1
Step-by-step explanation:
7(4x+1)−3x=5x−13
Distribute
28x +7 -3x = 5x -13
Combine like terms
25x+7 = 5x-13
Subtract 5x from each side
25x-5x +7 = -13
20x +7 = -13
Subtract 7 from each side
20x+7-7 = -13-7
20x = -20
Divide by 20
20x/20 = -20/20
x = -1
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
-15
Step-by-step explanation:
-3(-4-5x)= -18
12+15x= -18-12
15x= -30
x= -30÷15
x= -15
