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borishaifa [10]
3 years ago
7

analyze this situation and determine how much cookie dough is "wasted" when 3-inch cookies are cut. then have each team member c

alculate the amount of dough wasted when a cookie of a different diameter is used. compare results

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

The result is the same.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

Given the information:

  • square 12 inches wide
  • 3-inch diameter cookies are cut => its radius is: 1.5 inches

Hence we can find some information:

  • The area of the square is: 12^{2}  = 144 square inches
  • The area of a cookies is: r^{2}π = 3.14*1.5^{2} = 7.065 square inches
  • The total number of 3-inch cookies are: 4*4 =16

=> The total area of the cookies is: 16* 7.065 = 113.04 square inches

=> how much cookie dough is "wasted" when 3-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

If the diameter is increased to 4 inches => its radius: 2 inches, we have:

  • The area of a cookies is: r^{2}π = 2^{2} *3.14 = 12.56 square inches
  • The total number of 3-inch cookies are: 3*3 =9

=> The total area of the cookies is: 9* 12.56 = 113.04 square inches

=> how much cookie dough is "wasted" when 4-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

The result is the same.

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A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or \frac{8}{12} ft

= \frac{2}{3} ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= \frac{11}{12} ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k(\frac{2}{3})

k = 18

Work done (W) to stretch the spring by \frac{11}{12} ft will be

W = \int\limits^\frac{11}{12} _0 {kx} \, dx

    = \int\limits^\frac{11}{12} _0 {(18x)} \, dx

    = 18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0

    = 9(\frac{11}{12})²

    = 7.56 lb-ft

6 0
3 years ago
Jonas wants to serve serve 48 people one cup of tea each. How many gallons of tea must he prepare?
Aleks04 [339]

Answer:

3 gallons

Step-by-step explanation:

1 gallon=16 cups

48÷16=3

3 gallons makes 48 cups

6 0
4 years ago
Tanya and Reece each walked 4 miles on Monday. Reese also walked 4 miles on Tuesday and 4 miles on Wednesday . How many miles di
sammy [17]

Answer:

12 miles

Step-by-step explanation:

monday=4 miles

tuesday=4 miles

wednesday= 4 miles

4+4+4=12

4 0
3 years ago
18:a = 14:21 what does a equal?
elixir [45]

Answer:

is that lil huddy in your pfp lol (melanin king)

Step-by-step explanation:

8 0
3 years ago
According toThe Humane Society in 2009 33% of US households owned at least one cat and 56% of households who did own cats owned
taurus [48]

Answer:

<h2>21.4368 ≅ 21.44 million households owned at least two cats.</h2>

Step-by-step explanation:

Total number of households were 116 million.

Hence, 100% = 116 million.

33% of the total US households owned at least one cat.

Hence, the number of household having at least one cat is \frac{33\times116}{100} = \frac{3828}{100} = 38.28 million.

It is also given that 56% of that 38.28 million households owned at least 2 cats.

Hence, the number of households having 2 cats is \frac{56\times38.28}{100} = \frac{2143.68}{100} = 21.4368 million.

7 0
3 years ago
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