Answer:
(c) n(n+1)/√2
Step-by-step explanation:
√2+√8+√18+√32+...
1√2+2√2+3√2+4√2+...+n√2
- First term= √2
- Common difference= √2
- Sₙ= n/2(2√2+(n-1)√2)= n/2(n√2+√2)=n(n+1)√2/2= n(n+1)/√2
Option (c) is correct
Answer:
Variance of difference between pre-exam and post-exam grades = 10.8
Step-by-step explanation:
Correlation (X,Y) = Covariance (X,Y) / √ { Variance (X) . Variance (Y) }
Given : Correlation (Pre & post exam grade) = 0.9 ; Variance (Pre exam grade) = 0.90 ; Variance (Post exam grade) = 16
So, 0.9 = Covariance (X,Y) / √ { 16 x 9 }
0.9 = Covariance (X,Y) / 12
Covariance (X,Y) = 12 x 0.9 = 10.8
<h2>
Greetings!</h2>
Answer:
B)
Step-by-step explanation:
Y intercept:
Simply substitute all the x values with 0:
When x = 0:
3(0) - 2y = 18
Move the - 2y over to the other side making it a +2y:
0 = 18 + 2y
Move the +18 over to the other side making it a -18:
-18 = 2y
Divide both sides by 2:
-9 = y
So y intercept is:
<h3> (0 , -9)</h3>
X - intercept:
Simply substitute all the Y's with 0:
3x - 3(0) = 18
3x = 18
Divide both sides by 3:
x = 6
So the X intercept is:
<h3>(6 , 0)</h3>
This means that your guess of B is correct.
<h2>Hope this helps! </h2>
Answer:
7
Step-by-step explanation:
1) b. There are 10 100's in 1,000
2) c. This is what it is written in words