Given that plane P is parallel to the planes containing the base faces of the prism; then, if the plane meets the prism between the planes containing the hexagonal bases, then P meets the prism in a hexagonal region that is congruent (with the same size) to the bases of the prism.
Answer:
Either x+15 or x-17.
Step-by-step explanation:
Answer:
B. a reflection across X axis and then a dilation by a scale factor of 1.5
Step-by-step explanation:
As clear from the graph all the coordinates of image 2 are 1.5 times of image 1 so shape 2 is dilated by the scale factor 1.5.
It is evident from the graph that lines AO and A"O"are parallel to each other so shape 2 is the reflection of shape 1.
Now we calculate the magnitude of line AB
m1 = (y2-y1)/(x2-x1)
=(-3+6)/(-4.5=9)
=3/4.5
=1/1.5
=2/3
Next we calculate magnitude m2 of A"B"
m2= (2-4) /(-3+6)
=(-2/3)
Then we know Tan(180-∅) = -tan∅
similarly if m1=(-m2)
then the one line having magnitude m2 is the rotated image through X axis by 180° of the line having magnitude m1.
So the answer is B.
Answer:
48 Square Centimeters
Step-by-step explanation:
The red triangular exterior pieces are all equilateral triangles with some side length.
We don't need to know what that side length is. It doesn't matter.
The area of one red equilateral triangle is some area A.
There are 6 of these red triangles, so the red exterior triangular parts combine to a total area of 6*A.
The hexagon is composed of equilateral triangles as well.
Each of these blue equilateral triangles is congruent to any outer red triangle because the side length is the same.
Therefore, the 6 blue equilateral triangles composing this hexagon combine to get a total area of 6*A
The area of the star overall is 12*A because we have 6 blue triangles combining with the 6 red triangles.
There is a total of 12 triangles.
The yearly rate of appreciation is 6,333.3%
(I'm pretty sure I did that right)