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Mice21 [21]
3 years ago
8

Consider the following list of numbers.

Mathematics
1 answer:
kotykmax [81]3 years ago
8 0
121,129,52,47,516,682
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Find all values of x in the interval [0, 2π] that satisfy the equation. 7 sin(2x) = 7 cos(x)
cricket20 [7]
Turn sin(2x) into 2sin(x)cos(x) and solve.
the equation should be in the book.
you also need to know your unit circle
I might be wrong though

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Determine whether the triangles are similar. If so, write a similarity statement and name the postulate or the theorem you used.
neonofarm [45]
The first pair of triangles are similar.

Triangle ABC is similar to Triangle PQR.

I used the SSS theorem of congruency.

( side - side - side) since I knew the sides were equal I knew that they were congruent.

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The second pair of triangles are similar too.

Triangle ABC is similar to Triangle DEF.

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Since I knew what the sides were, I did some calculations and they all equalled 6...

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I hope that helps you out!! Any more questions??
6 0
4 years ago
Read 2 more answers
A brick of cheese is 3/4 inch thick. A deli cuts the brick of cheese into slices that are 1/10 inch thick. How many slices are c
marysya [2.9K]
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4 0
3 years ago
Hi could you please answer the following questions on upper and lower bounds. Please provide full working out for each answer. T
Nutka1998 [239]
Ok so I will do only one and only put the answer for the others
ok so nearest xmm means that you havet o find teh smalles then largest so



1. legnth times width=area
so find max and min area
5 mm eror
legnth=645
width=400
so the legnth and witdth could be area
640 (subtract 5 for rerror) and 395 (subtract 5 for error
or
650 (add 5 for error) and 405 (add 5 for error)

so areas could be
640 times 395=252800
650 times 405=263250
upper bound=263250 mm^2
lower bound=252800 mm^2
so basically subtract the error to find minimum possible area and then add error to original measues to find max possible area


2. upper bound=29 m
 lower bound=27 m


3. perimiter=2(L+W)
2((145-5)+(28-1))=lower bound=334 m
2((145+5)+(28+1))=upper bound=358 m


4. (35-1)(26-1)=lower bound=850 cm^2
(35+1)(26+1)=upper bound=972 cm^2


5. 2 sig figs (not sure about this question as much)
nonzeros are significant
30 is 1 sig fig since 0 is not significant
therfor
30.9 to 30.0
18=2 sig figs so that is alreight
upper bound of width=18
30.9 times 18=upper bound=556.2 cm^2
30.0 times 18=lower bound=540 cm^2


ANSWERS


1. upper bound=263250 mm^2
lower bound=252800 mm^2


2. upper bound=29 m
 lower bound=27 m


3. lower bound=334 m
upper bound=358 m


4. lower bound=850 cm^2
upper bound=972 cm^2



5. upper and lower bound o 18=18

upper bound=556.2 cm^2
lower bound=540 cm^2





3 0
3 years ago
I need help quick please
jok3333 [9.3K]

i’ll tell you on discord, add me there my user is ri#0511

6 0
3 years ago
Read 2 more answers
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