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ella [17]
3 years ago
8

Help please!! True Or False?

Mathematics
2 answers:
ahrayia [7]3 years ago
8 0
It’s a constant so it’s true. A constant is a number on it’s on or it can be a letter stranded for a fixed number
Sergio039 [100]3 years ago
3 0
True because it’s constant
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If a towns population currently at 50,000 experiences 5% growth every 10 years, what will its population be in 25 years
disa [49]

Answer:

56503

Step-by-step explanation:

this grows exponentialy so at the start it would be 50,000 growing by 5% every ten years. but since there is only 2 ten years in 25 years we must cut the percent in half making 2.5%

Step 1

(50,000×5%)+50,000= 52500

Step 2

(52500×5%)+52500= 55125

step 3

(55125×2.5%) +55125= 56503

5 0
2 years ago
I need help with this question​
4vir4ik [10]

Answer:

y = 3

Step-by-step explanation:

y/9 = 2/6

y/9 = 1/3 (dividing by 2in both numerator and denominator.)

CROSS MULTIPLYING WE GET

3y = 9*1

3y = 9

y = 3

4 0
3 years ago
Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
Photo attached please help
aniked [119]
C and E that is the answer
4 0
3 years ago
Simplify each expression (2a^4)^-3,a does not =0
Masja [62]

Answer:

3rd option.) 1/8a^12

Step-by-step explanation:

(2a⁴)^-3

=1/(2a⁴)³

=1/8a^12

8 0
2 years ago
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