-- The width of the school is ' W '. We don't know what that is yet,
but we're going to find out.
-- We're told that the length is 4 times as much. So the length is ' 4 W '.
-- Perimeter is (2 widths) + (2 lengths).
2 widths = 2 W
2 lengths = 8 W
Perimeter = 10 W
-- We're also told that the perimeter is 55m. That's just what we need.
10 W = 55 m
Divide each side of this equation by 10:
W = 5.5 m
There's the width !
The length of the hall is 4 times as much.
Length = 4 W = 22 m
Answer:
1 because then he would eat 6 in 6 hours .-.
Answer:
<h2> 22.2</h2>
Step-by-step explanation:
Step one
given the coordinates
ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)
AB=(-2,-2),(-1,3)
BC=(-1,3), (5, 3)
CD=(5, 3),(4, -2)
DA=(4, -2),(-2,-2)
The distance between points AB=
The distance between points BC=
The distance between points CD
The distance between points DA
Hence the perimeter = 5.1+6+5.1+6
= 22.2
Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
