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3 years ago

Use the function below to find F(3). FX) =1/3•4x

Mathematics

2 answers:

son4ous [18]3 years ago

7 0

Answer:

Step-by-step explanation:

kozerog [31]3 years ago

3 0

The answer is 4

its is four because u plug 3 in for x and 3 times 4 is twelve. twelve times 1/3 is 4

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Fill in the missing part of the analogy

steposvetlana [31]

Answer:

she/se jajdjgdgmggdukhmijauuuu

Step-by-step explanation:

jkiek3ke

7 0

3 years ago

X/2 is greater than or equal to -4

irga5000 [103]

$\frac{x}{2}$ ≥-4

Pretend the greater than or equal to sign is an equal sign, we will substitute it back in later.

x/2 = -4
Multiply both sides by 2 to get x alone
x = -8
Substitute the greater than or equal to sign back in and voila!
x≥-8

3 0

3 years ago

Find the tangent of angle A (giving brainliest and thanks to all!)

Shtirlitz [24]

Answer:

Option B, 8 / 6

Step-by-step explanation:

Tangent = Opposite / Adjacent

Tangent of ∠A = Opposite / Adjacent

Tan(A) = 8 / 6 which is the same as Option B

Hope this helps!

3 0

3 years ago

Dont get it wrong, if its wrong i fail, explain how you got your answer

damaskus [11]

Answer: 50.24

Area of a circle is pi times r^2

The r is 1/2 the d

So 8/2 = 4

Pi times 4^2= 50.24

7 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago