Answer:
x^2+y^2 = 3^2
Step-by-step explanation:
We need to eliminate the parameter t
Given:
x = 3 cos t
y = 3 sin t
Squaring the above both equations
(x)^2=(3 cos t)^2
(y)^2 =(3 sin t)^2
x^2 = 3^2 cos^2t
y^2=3^2 sin^2t
Now adding both equations
x^2+y^2=3^2 cos^2t+3^2 sin^2t
Taking 3^2 common
x^2+y^2=3^2 (cos^2t+sin^2t)
We know that cos^2t+sin^2t = 1
so, putting the value
x^2+y^2=3^2(1)
x^2+y^2 = 3^2
Hence the parameter t is eliminated.
Use the definition of absolute value.

The absolute value is always non-negative. So if
is already non-negative,
is unchanged. But if
is negative, then
because multiplying
by -1 makes it positive.
Now, if
, then by the definition of absolute value,

Answer:
33
Step-by-step explanation:
take the total and then subtract by 34 to get 33
Answer:
A5#A
Step-by-step explanation:
Answer:
(-3, -6)
Step-by-step explanation:
always start from the origin! Hope this helps!