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3 years ago

5 - 3(-2) + |-3| please explain

Mathematics

1 answer:

Natalija [7]3 years ago

7 0

Answer:

Step-by-step explanation:

=5+6+|-3|

=11+|-3|

=11+(-√3^2)

=11+3

=14

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cora says she doesn't need to know the y-intercept of a line to write its equation, just its slope and some other point on the l

Nadusha1986 [10]

Answer:

The equation of line with given slope that include given points is 3 y + x - 20 = 0

Step-by-step explanation:

According to Cora , if we know the slope and points on a line then we can write the equation of a line .

Since , The equation of line in slope-intercept form is

y = m x + c

<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>

So , From the statement said above it is clear that she is correct .

Now , Again

Given as :

Slope of a line is m = - $\frac{1}{3}$

That include points ( 2 , 6 )

Now from the equation of line as y = m x + c

∴ 6 = - $\frac{1}{3}$ ( 2 ) + c

Or, 6 = - $\frac{2}{3}$ + c

So , c = 6 + $\frac{2}{3}$

or, c = $\frac{18 + 2}{3}$

∴ c = $\frac{20}{3}$

So, The equation of line can be written as

y = - $\frac{1}{3}$ x + $\frac{20}{3}$

Or, 3 y = - x + 20

I.e 3 y + x - 20 = 0

Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer

8 0

3 years ago

[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =

kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = $1-\frac{_{n}^{12}\textrm{P}}{12^2}$

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= $\frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})$