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olya-2409 [2.1K]
3 years ago
9

Solve for f. d(e-f)=g

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Isolate the variable by dividing each side by factors that don't contain the variable.

f=e-g/d

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The regular price of an item is $35. the item is on sale with a discount of $10. what is the discount rate?
salantis [7]
About 29 percent. you would do 10*100/35=28.87 you would round up to 29 percent
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Answer:

1.32t

Step-by-step explanation:

Raise 1.08 to the 4th power. (1.08 ^1/4)^4t=1.36t

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3 years ago
1. Use complete sentences to explain how it is possible to get linear factors of a polynomial.
vazorg [7]
1.)If f(a) = 0, then x - a is a factor of the polynomial.

2.) x + 3 is a factor of the polynomial.
4 0
3 years ago
A biologist studied how cells grow by adding liquid protein to cell samples. She reported in her study that she divided 3/5 of a
r-ruslan [8.4K]

Answer: \dfrac{1}{5}\text{ of an ounce.}

Step-by-step explanation:

Given : A biologist studied how cells grow by adding liquid protein to cell samples.

She divided \dfrac{3}{5} of an ounce of liquid protein evenly among 3 cell samples.

Here , total quantity of liquid protein = \dfrac{3}{5} of an ounce

Total cell samples = 3

Now , Quantity of liquid protein given by her to each cell = (total quantity of liquid protein ) ÷ (3)

= \dfrac{3}{5}\times\dfrac{1}{3}=\dfrac{1}{5}\text{ of an ounce} .

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4 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
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