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kykrilka [37]
4 years ago
12

HELP PLZ :)

Mathematics
2 answers:
meriva4 years ago
8 0
The answer to this one is there is a 1/10 chance because there are ten balls and only one is a 0
Alenkasestr [34]4 years ago
3 0
1/10 since the ball are labeled 0-9 there is 10 balls and they are only guessing for 1 of them so it is 1/10 chance of getting the ball they pulled!
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Thx the picture I need help with it thx
Anon25 [30]
40x7=280

Your answer is $280

Hope this helped :D
~xo Melis
5 0
4 years ago
wyatt opend a savings account 4 years ago. the account earns 4%interest compounded quarterly if the current balance is $1,000.00
Doss [256]

Answer:

He deposited initially $852.82

Step-by-step explanation:

The rule of the compound interest is A=P(1+\frac{r}{n})^{nt}, where

  • A is the new amount
  • P is the initial amount
  • r is the rate in decimal
  • n is the period of the time
  • t is the time

∵ Wyatt opened a savings account 4 years ago

∴ t = 4

∵ The account earns 4% interest compounded quarterly

∴ r = 4% = 4 ÷ 100 = 0.04

∴ n = 4 ⇒ compounded quarterly

∵ The current balance is $1,000.00

∴ A = 1,000

→ Substitute these values in the rule above to find P

∵ 1,000 = P(1+\frac{0.04}{4})^{4(4)}

∴ 1,000 = P(1+0.01)^{16}

∴ 1,000 = P(1.01)^{16}

→ Divide both sides by  (1.01)^{16}

∴ 852.8212622 = P

→ Round it to the nearest cent (2d.p)

∴ P = 852.82

∴ He deposited initially $852.82

4 0
3 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
4 years ago
The graph of a function in the form f(x) a(x - h)2 +k is shown. Use the graph to find an equation for f(x).
seropon [69]
O.K.

(h; k) are the coordinates of the vertex.

On the graph are (3; 4), therefore we have:

f(x)=a(x-3)^2+4

We have the x-intercept (1; 0) → x = 1; y = 0.
Substitute them in the equation:

0=a(1-3)^2+4\\\\0=a(-2)^2+4\\\\4a+4=0\ \ \ |-4\\\\4a=-4\ \ \ \ |:4\\\\a=-1

so. We have the answer:

\boxed{f(x)=-(x-3)^2+4}

8 0
3 years ago
Please hurry it’s timed
frutty [35]

Answer:

I believe it is Option 1

Step-by-step explanation:

Since the fourth root of 81 will be 3 and of 16 will be 2.

4 0
3 years ago
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