Question

HELP PLEASE WILL MARK THE BRAINLIEST. Needs to be handed in tomorrow.

Answer 1

Given : ABCF is a Rectangle

⇒ AB = CF

Given : AB = 6 cm

⇒ CF = 6 cm

Perimeter of a Rectangle is given by : 2(Length + Width)

Given : Perimeter of the Rectangle = 20 cm

⇒ 2(6 + BC) = 20

⇒ 6 + BC = 10

⇒ BC = 4

Given : BD = 9

But, We can See that : BD = BC + CD

⇒ CD + 4 = 9

⇒ CD = 5

We know that :

✿  $\mathsf{Area\;of\;Trapezium\;is\;given\;by : (\frac{a + b}{2}) \times Height}$

Where : a and b are Lengths of Parallel Sides and Height is Length between those Parallel Sides

In the Given Trapezium :

The Parallel Sides are CD and EF and Height is CF

Given : EF = 3 cm

$\mathsf{\implies Area\;of\;the\;Given\;Trapezium = (\frac{5 + 3}{2}) \times 6}$

$\mathsf{\implies Area\;of\;the\;Given\;Trapezium = 24\;cm^2}$