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3 years ago

Help me please because i'm confused

Mathematics

1 answer:

Fittoniya [83]3 years ago

8 0

Answer:

She does have enough turkey for the recipe. She has enough because 4.35 is greater then 4 1/3. 4 1/3= 4.3333... and 4.35 is greater then 4.3333...

Step-by-step explanation:

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- 5x = -x - 48<br> x = -11<br> X = 12

Andreas93 [3]

Answer:

B- x=12

Step-by-step explanation:

-5x=-x-48

-12+-48

-12. -12

-60=-5x

-5. -5

x=12

4 0

3 years ago

Help solve for “q”<br> —————————————

VMariaS [17]

Digram:-

$\\$

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}$

$\\$

STEP :-

$\dashrightarrow \tt(4q - 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ}$

{Linear pair}

$\\ \\$

$\dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ} - {117}^{ \circ}$

$\\$

$\dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}$

$\\$

$\dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}$

$\\$

$\dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}$

$\\$

$\dashrightarrow \tt4q =64{}^{ \circ}$

$\\$

$\dashrightarrow \tt \: q = \dfrac{64}{4}^{ \circ}$

$\\$

$\dashrightarrow \tt \: q = \dfrac{16 \times 4}{4}^{ \circ}$

$\\$

$\dashrightarrow \tt \: q = \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}$

$\\$

$\dashrightarrow \tt \: q = \dfrac{16}{1}$

$\\$

$\dashrightarrow \bf q = 16 \degree$

$\\ \\$

Verification:

$\\$

$\dashrightarrow \tt(4 \times 16- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ}$

$\\$

$\dashrightarrow \tt(64- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ}$

$\\$

$\dashrightarrow \tt63^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ}$

$\\$

$\dashrightarrow \tt180^{ \circ} = 18 {0}^{ \circ}$

$\\$

LHS = RHS

HENCE VERIFIED!

8 0

3 years ago

11- Pre-algebra problem pls help

Juliette [100K]

Answer:

The answer is c

Step-by-step explanation:

3 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

Please answer these all of these (If you can), and I know you can search it on go ogle so I need a detailed show of how you did

Xelga [282]

1. Answer is x = 1
Explanation: Rearrange terms
-22 + 8c = 28x - 42
Add 22 to both sides of the equation
8x - 22 = 28x - 42
8x - 22 + 22 = 28x - 42 + 22
Simplify
8x = 28x - 20
Subtract 28x from both sides of the equation
8x = 28x - 20
8x - 28x = 28x - 20 - 28x
Simplify
-20x = -20
Divide both sides of the equation by the same term
-20x/-20 = -20/-20

2. Answer is x = -8
Rearrange terms
-11x - 2 = 6 - 10x
-11x - 2 = -10x + 6
Add 2 to both sides of the equation
-11x - 2 = -10x + 6
-11x - 2 + 2 = -10x + 6 + 2
Simplify
-11x = -10x + 8
Add 10x to both sides of the equation
-11x = -10x + 8
-11x + 10x = -10x + 8 + 10x
Simplify
-x = 8
Divide both sides of the equation
-x = 8
-x/-1 = 8/-1
Simplify
x = -8

3. Answer is x = 7
Rearrange terms
4x + 8 = -13 + 7x
Subtract 8 from both sides of the equation
4x + 8 - 8 = 7x - 13 - 8
Simplify
4x = 7x - 21
Subtract 7x from both sides of the equation
4x = 7x - 21
4x - 7x = 7x - 21 - 7x
Simplify
-3x = -21
Divide from both sides
-3x = -21
-3x/-3 = -21/-3
answer is x = 7

4. Answer is x = -15
Subtract 8 from both sides
2x + 8 = x - 7
2x + 8 - 8 = x - 7 -8
Simplify
2x = x - 15
Subtract x from both sides of the equation
2x = x - 15
2x - x = x- 15 - x
Simplify
x = -15

Tried to be detailed lol hope this helps!

5 0

3 years ago