Answer:
B. Increases the expected present value of lease cash flows to the owner
Explanation:
A lease option gives a right but not the obligation to the renter of the property to buy the said property at today's current market price upon the expiry of lease term.
Lease option is similar to an option contract, the difference being, here instead of securities, leased property serves as the underlying asset and instead of option premium, the renter pays a premium each year in addition to the rental charges.
Lease cash flows refer to the present value of future cash flows which the lessor/owner receives in the form of lease rentals plus the added premium each year.
The more the benefits under lease option clause, the higher the premium charged and thus, more would be the future receipts of owner which would increase the expected present value of lease cash flows to the owner.
Answer:
demand for pesos would fall and supply would rise. their value would decrease as a result
Explanation:
Inflation is a persistent rise in general price level.
When there is high inflation in a country, the demand for the currency would fall because the value of the currency is low. this fall in demand coupled with the excess supply of the currency would lead to a fall in the value of the currency.
Answer:
a. 40 % and $630,000
b. $ 270,000
Explanation:
The contribution margin ratio = Contribution ÷ Sales
The dollar sales volume required to break even = Fixed Cost ÷ contribution margin ratio
the margin of safety (in dollars) - company sells 20,000 units = Expected Sales - Break even Sales
<span>20% is the maximum speed up possible for this program.
For this problem, let's assign the time of 1 for the task when using a single processor. Now let's assume that we have an infinite number of processors available to handle the portion of the program that can be executed in parallel so that the execution time for that portion will be 0. That means that the total execution time with an infinite number of processors will be
1 * (0.80 + 0) = 1 * 0.80 = 0.80
So at best, the parallel program will take 80% of the time for the single threaded version. So the speed increase will be
(1 - 0.80) / 1 = 0.20/1 = 0.20 = 20%</span>
