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3 years ago

What is the equation of the line that passes through the point (3,2) and has a slope of -5/3?

1 answer:

8 0

Answer= Y=-5/3x+7

First substitute (3,2) into the equation y=-5/3x +b which gives you 2=-5/3x+b. Solve for b, then put the equation into slope-intercept form.

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A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0

3 years ago

After sharing with the class, Dana has 4/12 of her cupcakes left. What is the fractional part of the cupcakes did she share with

kotykmax [81]

She shared 2/3 of her cupcakes

7 0

3 years ago

Read 2 more answers

Evan and Eileen Carter are husband and wife and file a joint return for 2019. Both are under 65 years of age. They provide more

S_A_V [24]

Answer:

The correct answer is b) four.

Step-by-step explanation:

Evan and Eileen Carter must submit a separate statement as dictated by the requirements for the claim.

In the case of the daughter, she no longer meets the requirement of a qualified child because she is over 24 years old; but qualifies as an eligible relative, and also, the income of her scholarship is not enough, so she needs the help of her parents to cover her expenses.

The couple also provides support in all expenses of Evan's great-grandmother; although Belinda lives in an asylum, the Carter can claim the exemption since, for qualified relatives, they do not ask as a mandatory requirement that they live in the same place.

And finally, Peggy cannot request an exemption since she is not a qualified relative, so she does not fall within the exceptions to claim, even if she lives in Evan and Eileen Carter´s house.

Therefore, the Carter can claim four dependency exemptions, one for each person that are Evan, Eileen, Pamela, and Belinda.

I hope this information can help you.

7 0

3 years ago

Help me for brainlist no cap

Schach [20]

Answer:

Step-by-step explanation:

So first, you find the area of a rectangle, which would be 15 * 30 = 450. Next, find the area of the semicircle by doing $\pi *r^2 / 2$ (you have to divide by 2 because it's only have a circle).