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3 years ago

What is the equation of the line that passes through the point (3,2) and has a slope of -5/3?

1 answer:

8 0

Answer= Y=-5/3x+7

First substitute (3,2) into the equation y=-5/3x +b which gives you 2=-5/3x+b. Solve for b, then put the equation into slope-intercept form.

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Simplify 5(3x+4) Please and thank you!

HACTEHA [7]

Answer:

15x+20

Step-by-step explanation:

you multiply 3x×5 and you get 15 and then you multiply 5×4 and you get 20

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3 years ago

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A new theater is being built for the city ballet. The balcony has 200 seats. The floor has 10 rows with x seats in each row. The

Andreyy89

Answer:

Step-by-step explanation:

Because I got it right

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3 years ago

At a large local university, 40% of the students live in the dormitories. A random sample of 80 students is selected for a parti

likoan [24]

Answer:

0.9325

Step-by-step explanation:

Given

n = sample size = 80

p = probability = 0.4

q = 1 – p = 0..6

standard deviation for the proportion = √ (p * q) /n = √(0.4*0.6)/80 = 0.0547

for the proportion mean is 0.4

now we can find z and the probability

P (0.3<mean<0.5) = P((0.3– 0.4)/0.0547 < z < (0.5– 0.4)/0.0547)

P (0.3<mean<0.5) = P(-1.828< z < 1.828)

Using a z table

P (0.3<mean<0.5) = 0.9325

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3 years ago

Trig question -- please help if you can!

yanalaym [24]

$\bf \textit{Sum and Difference Identities}
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sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)
\\\\
cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)\\\\
-------------------------------\\\\
y=r[cos(\theta +R)]\implies y=r[cos(\theta )cos(R)-sin(\theta )sin(R)]
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y=rcos(\theta )cos(R)-rsin(\theta )sin(R)
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\\\\\\
z=rsin(\theta )cos(R)+rcos(\theta )sin(R)$

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4 years ago

How to write 4 - 5h in verbal expression

aleksandr82 [10.1K]

Four minus five times a number

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3 years ago