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Nana76 [90]
2 years ago
8

The sum of the squares of two consecutive even integers is 884. determine the integers.

Mathematics
1 answer:
Digiron [165]2 years ago
5 0

Answer:

(2x+1)(1) = 84. 2x+1= 84. 2x = 83.

Step-by-step explanation:

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Urgent
Damm [24]

The result of our calculations about the rate and time are:

  • r=d/t
  • 200000m/hr
  • 200km/hr
  • km/hr

<h3>What is rate?</h3>

Rate can be regarded as the given object with respect to time.

falcon flies= 800,000 meters

t= 4 hours

We were given the  formula as (d = rt)

d= distance

r = rate

t = time

We can make our calculations as:

part a:

r=d/t

part b:

falcon's rate in meters per hour = 800,000 meters / 4 hours = 200000m/hr

part c:

falcon's rate in kilometers per hour=(200000m/hr *(1/1000)=200km/hr

part d:

km/hr

Learn more about rate at:

brainly.com/question/8728504

#SPJ1

4 0
2 years ago
Recall Marginal Cost is the derivative of Total Cost, and Fixed Cost is the cost of producing zero units.
olga nikolaevna [1]

Answer:

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

Step-by-step explanation:

The Marginal Cost is given by the following function

MC(q) = 200*(q+9)^{-5}

The total cost function is the integrative of the marginal cost function. So:

TC(q) = \int {MC(q)} \, dq

TC(q) = \int {200*(q+9)^{-5}} \, dq

TC(q) = -50*(q+9)^{-4} + K

In which K, the integrative constant, is the fixed cost. So K = 4000.

1. Find the total cost of producing 91 units of ACME rocket fuel.

This is TC(91).

So

TC(91) = -50*(91+9)^{-4} + 4000 = 3999.99

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

8 0
3 years ago
Can someone solve this for me? i also would like to know how you did (worked it out)
Nitella [24]

Answer:

it's

Step-by-step explanation:

(2f+2)(2f-2)

(2f^2-2^2)

7 0
2 years ago
Read 2 more answers
Need help again asap please! Find the sum of the first 30 terms of the sequence below an=3n+2
hoa [83]

S_{30} = 1455

generate a few terms of the sequence using a_{n} = 3n + 2

a_{1} = ( 3 × 1) + 2 = 5

a_{2} = (3 × 2) + 2 = 8

a_{3} = (3 × 3 ) + 2 = 11

a_{4} = (3 × 4 ) + 2 = 14

a_{5} = ( 3 × 5 ) + 2 = 17

the terms are 5, 8, 11, 14, 17

these are the terms of an arithmetic sequence

sum to n terms is calculated using S_{n} = \frac{n}{2} [ 2a + (n-1)d]

where a is the first term and d the common difference

d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and a_{1} = 5

S_{30} = \frac{30}{2} [( 2 × 5) + (29 × 3) ]

= 15( 10 + 87) = 15 × 97 = 1455



3 0
3 years ago
Read 2 more answers
Calculate the density of the steel in g/cm^3
faust18 [17]
The answer is 8 gram/cm^3
Hope this helps
6 0
3 years ago
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