Question

The graph below represents the linear equation y = one-half x minus 3. On a coordinate plane, a line goes through (0, negative 3) and (6, 0). A second linear equation is represented by the data in the table. x y –1 1 0 0 2 –2 3 –3 What is the solution to the system of equations? (–2, –4) (1, –1) (2, –2) (4, –4)

Answer 1

Answer:

(C) (2, -2)

Step-by-step explanation:

Given the linear equation: $y=\dfrac12x-3$

A second linear equation is given by the table:

$\left|\begin{array}{c|cccccc}x&-1&0&2&3\\y&1&0&-2&-3\end{array}\right|$

Clearly, this is a graph of y=-x as each y-value is a negative of its x-value.

Therefore if:

$y=\dfrac12x-3; and \\y=-x\\Then:\\\dfrac12x-3=-x\\\dfrac12x+x=3\\\dfrac32x=3\\3x=6\\x=2$

Recall: y=-x

Therefore: y= -2

Therefore, a solution to the system of equations is (2, -2)

Answer 2

Answer:

(2, -2)

Step-by-step explanation:

Put 2 in for x and -2 in for y. Also I got it correct on Edge.