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astraxan [27]
3 years ago
12

You have nickels,dimes,and quarters to make a call that costs $0.75 how many different combinations of coins can you use to pay

for the call
Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0
17 possible combinations

1.
  3 quarters
2.  2 quarters, 1 dime, 1 nickel
3.  2 quarters, 3 nickels
4.  1 quarter, 5 dimes
5.  1 quarter, 4 dimes, 2 nickels
6.  1 quarter, 3 dimes, 4 nickels
7.  1 quarter, 2 dimes, 6 nickels
8.  1 quarter, 1 dime, 8 nickels
9.  1 quarter, 10 nickels
10.  7 dimes, 1 nickel
11.  6 dimes, 3 nickels
12.  5 dimes, 5 nickels
13.  4 dimes, 7 nickels
14.  3 dimes, 9 nickels
15.  2 dimes, 11 nickels
16.  1 dime, 13 nickels
17.  15 nickels
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Since the new cost is 144 pounds and this is 20% more,  this is 120% of the original price. Remember 100+20 = 120. To find the original price set up a proportion with these values:

\frac{144}{x}=\frac{120}{100}

Solve for the original price by cross multiplying numerator with denominator.

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120x = 14400

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