If a catering company provided 18 bottles of soda and 30 bottles on a table at a party then they may cover atmost 6 number of tables if they wanted table have the same number of each type of bottle with no bottle flip diver.
Given that a catering company provided 18 bottles of soda and 30 bottles on a table at a party they wanted table have the same number of each type of bottle with no bottle flip diver.
To find the greatest number of tables we need to find the H.C.F of 18 and 30.
18=2*3*3*1
30=2*3*5*1
H.C.F=2*3
H.C.F=6
Hence if a catering company provided 18 bottles of soda and 30 bottles on a table at a party then they may cover atmost 6 number of tables if they wanted table have the same number of each type of bottle with no bottle flip diver.
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Answer:
q02 because it is showed the most times
Answer:
m=-2/5
Step-by-step explanation:
m=y2-y1/x2-x1
m=-4-(-6)/-2-3
m=-4+6/-5
m=-2/5
Answer:
im answering this for the points and also u lied about how many points i would be getting. -.-
Step-by-step explanation:
answer is C i think
