After putting the value of y from the second equation to the first equation, the resultant equation is 
.
GIven:
The equations are:
It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,
Now, put this value of y in the first equation as,
Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is .
For more details about equations, refer to the link:
brainly.com/question/2263981
There asking for the equation, and the possible answers are
y = 2x + 6
y = −one halfx + 3
y = −one halfx + 6
y = 2x + 3
The general line through (a,b) and (c,d) is
(c-a)(y-b)=(d-b)(x-a)
Here that's
(1 - - 5)(y - - 5) = (4 - -5)(x - - 5)
6(y+5)=9(x+5)
6y + 30 = 9x + 45
-15 = 9x - 6y
3x - 2y = -5
Answer: 3x - 2y = -5
We could put that in slope intercept form,
2y = 3x + 5
y = (3/2) x + 5/2
Answer: y = (3/2) x + 5/2
Y = 3 because in a rectangle, the diagonals are ALWAYS congruent. so you would have:
5y - 2 = 4y + 1
-4y+2 -4y + 2
y = 3
01100001 = 97 64+32+1=97 (if the leading bit is 0 it's usually not shown)
very easy
8 bits
Bit 1 Value 128
Bit 2 value 64
Bit 3 value 32
Bit 4 value 16
Bit 5 value 8
Bit 6 value 4
Bit 7 value 2
Bit 8 value 1
