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3 years ago

The water level of a tank every minute since it began filling is indicated by segments A, B, and C on the graph below.

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

Answer:

B C A

Step-by-step explanation:

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Ty very much! Please help? :))

wlad13 [49]

Answer:

Exact Form: 

$\frac{8}{3}$

Decimal Form:

$2.6$

Mixed Number Form:

$2\frac{2}{3}$

Hope this helps :)

-ilovejiminssi♡

4 0

2 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago

Sinplify this expression -3(10x+4y)+6(6x-2y)

ad-work [718]

Answer:

6x-24y

Step-by-step explanation:

Step 1: -30x-12y+36x-12y

Distribute-3 to 10x and 4y

Then distribute 6 to 6x and -2y

Step 2: 6x-24y

After that add up like terms

3 0

3 years ago

What is 3/3 simplified

REY [17]

Answer:

three over three is simplified to be the value 1

Step-by-step explanation:

your answer is 1

5 0

3 years ago

Read 2 more answers

On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if

postnew [5]

To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12

ANSWER:
5/12 of the fish she catches are trout

7 0

3 years ago