Answer:
work is attached and shown
Answer:
Step-by-step explanation:
First put the lower limit, i.e., x=0,
F(x)=8cos[2(0)]=8cos(0)=8(1)=8
;cos(0)=1
Now,put the upper limit of given interval, i.e., x = π,
F(x)=8cos[2(π)]=8cos(2π)=8(1)=8
;cos(2π)=1
Cubic root (8)^x = 8^(x/3)
Answer: Option d. 8^(x/3)
4x - 5y = -15
y = -3x + 22
Plug in your y= equation into the y variable in the other equation
4x - 5 (y) = -15
^^
y = (-3x + 22) = -15
4x - 5 (-3x + 22) = -15
Distribute
4x + 15x - 110 = -15
Combine like terms and add 110 over to -15
19x = 95
Then, divide the whole equation by 19
x = 5
Then, plug in your x into your y= equation
y = -3 (5) + 22
y = -15 + 22
y = 7
<em><u>x = 5</u></em>
<em><u>y = 7</u></em>
<em><u>(5, 7)</u></em>
