Do recall that squaring and the *radical sign* cancel each other out... like so:(

)

= a
When you put it that way, it isn't enough :P
(

)

= a
(

)

=?
so you start with
(

)

=

8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous
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➷ You may have forgotten to add the options
However, you can collect like terms
In other words, collect the 'x' values and collect the numbers
5x + 18x = 23x
-12 - 4 = -16
Thus, your answer would be 23x - 16.
Any further questions, let me know.
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Answer:
1509
Step-by-step explanation:
Answer: is this 8th grade math or high school or college because i am in 8th grade
Step-by-step explanation: