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3 years ago

8

A box of 24 greeting cards is sold at a gift shop for $3.00. The cost to the store is $2.40. What is the markup as a percentage

of cost?

1 answer:

Brut [27]3 years ago

6 0

Answer:

25%

Step-by-step explanation:

formula for percent markup/discount= absulute value of original-new/original

plug the numbers in

(2.40-3.00/2.40) absolute value=0.25

0.25 as a percent is 25%

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3y-3.5/3y+6=17/25.5. find the value of y. give the scale factor of the polygon

Mekhanik [1.2K]

Hi the answer to your question is

((3y - 3.5) / (3y + 6)) * 25.5 = (17 / 25.5) * 25.5

((3y - 3.5) / (3y + 6)) * 25.5 = 17 (76.5y - 89.25) / (3y + 6) = 17

((76.5y - 89.25) / (3y + 6)) * (3y + 6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25

25.5y = 191.25

y = 191.25 / 25.5

<span>y = 7.5</span>

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2 years ago

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Step-by-step explanation:

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3 years ago

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True of false: 0.4< 0.400

LenaWriter [7]

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Step-by-step explanation:

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Pls only do this if yk it because i’m giving correct answer brainliest! :))

Leno4ka [110]

Answer:

$x=2+\frac{1}{2}\sqrt[]{21}$

or

$x=2-\frac{1}{2}\sqrt{{21}$

Step-by-step explanation:

$4x^2-16x-26=-21$

Add 21 on both sides.

$4x^2-16x-26+21=-21+21$

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c=-5

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$x=\frac{16\frac{+}{}\sqrt[]{336} }{8}$

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$x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}$

$x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}$

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$x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}$

$x=2+\frac{1}{2}\sqrt[]{21}$

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2 years ago

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