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3 years ago

Multiply (2x3+3x2+10x)(8x4)

Mathematics

1 answer:

Serga [27]3 years ago

8 0

Answer: 16x7 + 24x6 + 80x5

Step-by-step explanation:

( 2x3 + 3x2 + 10x) (8x4)

re-arranging the equation

8x4 ( 2x3 + 3x2 +10x)

expanding the bracket

16x7 + 24x6 + 80x5

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Work out the nth term in 9 6 3 0

Angelina_Jolie [31]

Answer:

nth term--n+3

Step-by-step explanation:

numbers increase by add three each time

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3 years ago

Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a

Zielflug [23.3K]

Answer:

The area of the associated sector is $\frac{25}{24}\pi \ in^{2}$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=5\pi\ in$

substitute and solve for r

$5\pi=2\pi r$

$r=2.5\ in$

step 2

Find the area of the circle

we know that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=2.5\ in$

substitute

$A=\pi (2.5^{2})=6.25\pi\ in^{2}$

step 3

Find the area of the associated sector

we know that

$2\pi\ radians$ subtends the complete circle of area $6.25\pi\ in^{2}$

by proportion

Find the area of a sector with a central angle of $\pi/3\ radians$

$\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}$

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3 years ago

Which of the following situations could be represented by the expression - 14+ (- 7)?

RUDIKE [14]

Answer:

Matt's

Step-by-step explanation:

he has to give away $14 (-14)

and also $7 (-7)

The others have positive numbers.

4 0

3 years ago

What is the area of a circle if half of it is 22 inches

Kobotan [32]

Answer: The answer is 44.

Step-by-step explanation: The answer is 44 because if half the area of the circle is 22 all you have to do is 22+22 or 22*2.

22+22=44 22*2=44

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3 years ago

Suppose that A is nonsingular. Prove that its inverse A-1 is unique. [Hint: Show that if there exists two matrices, B and C, suc

Bogdan [553]

Answer with Step-by-step explanation:

Let A is non-singular

$\mid A\mid\neq 0$

We have to prove that $A^{-1}$ is unique.

Suppose B and C are inverse of A such that

$BA=I$ and AC=I

By using property $AA^{-1}=A^{-1}A=I$

$C=C$

$(BA)C=B(AC)$

$I\cdot C=B\cdot I$

$C=B$

Hence, the inverse of A is unique.

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3 years ago