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2 years ago

What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?

Mathematics

2 answers:

Over [174]2 years ago

8 0

Answer:

x = –4 ± 2 $\sqrt{3}$

Step-by-step explanation:

Katyanochek1 [597]2 years ago

3 0

Answer:

Step-by-step explanation:

assuming it is $x^{2} +8x+4$

Using Quadratic formular -

a - 1

b - 8

c - 4

$x= \frac{ -8 -,+ \sqrt{(8^2) - 4 (1)(4)}}{2(1)} \\\\$

$x = \frac{-8 +,- \sqrt{48} }{2}\\\\$

$x = \frac{-8+,- 4\sqrt{3} }{2}$

$x = {-4+,- 2\sqrt{3} }$

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Akimi4 [234]

Answer:

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Step-by-step explanation:

Explanation:

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2 years ago

Can anyone explain those marked steps in case (iii)

Tema [17]

$\cos\dfrac{3x}2=\cos\left(\dfrac\pi2+\dfrac x2\right)$
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follows from the fact that the cosine function is $2\pi$ -periodic, which means $\cos x=\cos(2\pi+x)$ . Roughly speaking, this is the same as saying that a point on a circle is the same as the point you get by completing a full revolution around the circle (i.e. add $2\pi$ to the original point's angle with respect to the horizontal axis).

If you make another complete revolution (so we're effectively adding $4\pi$ ) we get the same result: $\cos x=\cos(4\pi+x)$ . This is true for any number of complete revolutions, so that this pattern holds for any even multiple of $\pi$ added to the argument. Therefore $\cos x=\cos(2n\pi+x)$ for any integer $n$ .

Next, because $\cos(-x)=\cos x$ , it follows that $\cos x=\cos(2n\pi-x)$ is also true for any integer $n$ . So we have

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2 years ago

Given f(x) = 4x - 6 and g(x) = f(2x), write an equation for g.

AysviL [449]

f(x)=4x-6

g(x) = f(2x)

Substitute 2x into the first equation, which you get

f(2x)=8x-6

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1 year ago

Factor Completely.<br> 30r^2 + 30r + 75.

kari74 [83]

Answer:

15(2r^2+2r+5)

Step-by-step explanation:

I'm more of a guess and check type of person, but 15 x 2r^2 = 30r^2, 15 x 2r = 30r, and 15 x 5 = 75

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2 years ago

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Sergio [31]

Answer:

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4 0

2 years ago