Question

What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?

Answer 1

Answer:

x = –4 ± 2$\sqrt{3}$

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

assuming it is $x^{2} +8x+4$

Using Quadratic formular -

a - 1

b - 8

c - 4

$x= \frac{ -8 -,+ \sqrt{(8^2) - 4 (1)(4)}}{2(1)}$

$x = \frac{-8 +,- \sqrt{48} }{2}$

$x = \frac{-8+,- 4\sqrt{3} }{2}$

$x = {-4+,- 2\sqrt{3} }$