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4 years ago

Name the type of special pairs of angles shown.

Mathematics

2 answers:

Elanso [62]4 years ago

6 0

Answer:

So WXY and YXZ are supplementary

Step-by-step explanation:

These angles form a straight line, which is 180 degrees. Supplementary angles are 180 degrees.

So WXY and YXZ are supplementary

Ipatiy [6.2K]4 years ago

5 0

Answer:

Supplementary

Step-by-step explanation:

These two angles would add up to 180 degrees. In other words the total of these two angles would make a straight line. Therefore, they are supplementary angles.

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12.

pashok25 [27]

Last year, the average math SAT score for students at one school was 475. The headmaster then introduced a new teaching method hoping to improve scores. This year, the mean math SAT score for a sample of students was 491. The headmaster concluded that the new teaching method produces higher SAT scores. The problem with reporting results this way is voluntary response. The information of how the teaching method isnot mentioned.

8 0

4 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

A.) 10 B.) 25 C.) 20 D.) 15

Sergio [31]

2x+4=10
2x=6
x=3
2(3)+4= 10
(plus, on parallelograms like that, parallel sides are equal to each other)

7 0

3 years ago

You purchased a 1.5-liter bottle of olive oil for $11.69. What was the cost per fluid ounce?

dlinn [17]

It would be approximately 23 cents per fluid ounce.

7 0

3 years ago

Find the area of a compound shape Can you please explain

gtnhenbr [62]

Answer:

$A=292.53~m^2$

Step-by-step explanation:

Area of a Compound Shape

The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.

The area of a circle of radius r is:

$A_c = \pi r^2$

The area of a triangle of base b and height h is:

$\displaystyle A_t=\frac{b.h}{2}$

Calculate the area of the circle:

$A_c = \pi 8^2$

$A_c = 64\pi$

Area of half the circle:

$A_c/2 = 32\pi~m^2$

Area of the triangle:

$\displaystyle A_t=\frac{24\cdot 16}{2}$

$A_t=192~m^2$

The area of the shaded shape is:

$A=32\pi~m^2+192~m^2$

Substituting the value of pi:

$\mathbf{A=292.53~m^2}$

4 0

3 years ago