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Zarrin [17]
3 years ago
14

alan drew a polygon with four sides and four angle. All four sides are equal. None of the angle are right angle. What figure did

alan draw?
Mathematics
1 answer:
Nastasia [14]3 years ago
4 0
Alan drew a quadrilateral that is a parallelogram and a rhombus.
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Express the function graphed on the axes below as a piecewise function.
dangina [55]

Answer:

y = 2/3x +6  for x< -3

y = 2/3x +1     for x> 3

Step-by-step explanation:

The graph is a line for  x < -3

( - 6,2) and ( -3,4)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point ( -6,2)

y -2 = 2/3(x - -6)

y -2 = 2/3(x +6)

y-2 = 2/3 x +4

y = 2/3x +6 x< -3

The graph is a line for  x > 3

(3,3) and ( 6,5)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 5-3)/(6-3) = 2/ (3) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point (6,5)

y -5 = 2/3(x - 6)

y-5 = 2/3 x -4

y = 2/3x +1   x> 3

8 0
3 years ago
Solve the equation 2x+3/3 - 3x/2=-4<br>Fast please
alina1380 [7]

Answer:

x = 6

Step-by-step explanation:

Assuming the equation is

\frac{2x+3}{3} - \frac{3x}{2} = - 4

Multiply through by 6 ( the LCM of 3 and 2 ) to clear the fractions

2(2x + 3) - 9x = - 24

4x + 6 - 9x = - 24

- 5x + 6 = - 24 ( subtract 6 from both sides )

- 5x = - 30 ( divide both sides by - 5 )

x = 6

6 0
3 years ago
3x - 3y = -15<br> -x + y = 5
Katyanochek1 [597]

Answer:

I don't understand what you're asking. can you put a question on this?

4 0
3 years ago
Using any five itegers from 1 to 10 what is the greatest possible mean of the 5 numberes if the median is 4?
BartSMP [9]
That would  a set of 5 numbers in ascending order with  4 being the middle one and the other 4 being the highest possible So it is

2, 3, 4, 9, 10

Mean is 28/5  = 5.6 answer

( I am assuming that each number is different)

Of duplicates is allowed then its 4 4 4 10 10  whose mean is 6.4
5 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Mashutka [201]

<h2> Option A is the right option.</h2>

please see the attached picture for full solution..

Hope it helps..

Good luck on your assignment...

4 0
2 years ago
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