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3 years ago

How do I do this problem? 3/5 x 3= mixed fraction

Mathematics

2 answers:

DochEvi [55]3 years ago

5 0

Answer:

1 4/5

Step-by-step explanation:

3/5 * 3/1 .....3 is the same as 3/1.....now just multiply them and u get 9/5.....now this is an improper fraction (the numerator is larger then the denominator)....u can turn improper fractions into mixed numbers (where u have a whole number and a fraction).

9/5.....how many times does 5 go into 9 without going over ?....it goes in there 1 time....so that is ur whole number.....5 x 1 = 5....u need 4 more to get to 9....that remainder 4 is ur numerator....and put that over ur original denominator.

so as a mixed number, 9/5 = 1 4/5

Vinil7 [7]3 years ago

4 0

Answer:9/5

Step-by-step explanation:

You might be interested in

Which of the following is the equation of a line perpendicular to the line

Taya2010 [7]

Answer:

A. - 2x + 3y = 21

Step-by-step explanation:

The perpendicular lines have opposite reciprocal slopes.

The given line has a slope of:

m = -3/2

The perpendicular slope is:

m = 2/3

And its y-intercept is:

9 = 2/3*3 + b
b = 7

The line is:

y = 2/3x + 7

Convert this into standard form and compare with answer choices:

3y = 2x + 21
- 2x + 3y = 21

Correct choice is A

3 0

2 years ago

A number is called evil if it has 666 in it. How many 7 digit numbers are evil?

defon

Step-by-step explanation:

There are 5 different positions of 666:

666////

/666///

//666//

///666/

////666

The forward dashes represent any number from 0 to 9.

Case 1: "666////"

Number of ways = 10⁴ = 10,000.

Case 2: The other positions.

Since the 1st forward dash cannot be 0 (leading digit),

Number of ways for each position = 9 * 10³ = 9,000

Number of ways for all 4 positions = 9,000 * 4 = 36,000.

Total evil numbers = 10,000 + 36,000 = 46,000.

5 0

2 years ago

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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