(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
__________________
-11x^2-5x-3
-(-11x^2-33x-33)
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28x+30
So our remainder will be 28x+30
S+7. Tell your teacher never to use s as a variable ever again.
Answer:

Step-by-step explanation:
Soh-cah-toa is a great way to remember:

You just remember the first letters : sine= opposite/hypotenuse , for example.