Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).

Mathematics

1 answer:

zavuch27 [327]3 years ago

3 0

Answer:

X=16

Step-by-step explanation:

10x-8=9x+8

First you have to simplify.

10x-9x=1x

So now the equation looks like this

x-8=8

Now you have to get x by itself

-8+8=0 and we have to do the same thing on both sides of the equal sign 8+8=16

The equation now looks like this x=16

And that's your answer

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dimaraw [331]

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7^3

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3 years ago

A distributor receives a large shipment of components. Thedistributor would like to accept the shipment if 10% or fewer ofthe co

posledela

Answer:

a. 0.2639 or 26.39%

b. 0.6242 or 62.42%

Step-by-step explanation:

This problem can be treated as a binomial model with probability of success p = proportion of defectives in the batch.

Number of trials (n) = 10.

For any number of successes 'k', the probability is:

$P(X=k) = \frac{n!}{(n-k)!k!}*p^k*(1-p)^{n-k}$

a. If p =0.10, what is P(x >1):

$P(X>1) = 1- P(X=0)-P(X=1)\\P(X>1) =1- \frac{10!}{(10-0)!0!}*0.10^0*(1-0.10)^{10-0}- \frac{10!}{(10-1)!1!}*0.10^1*(1-0.10)^{10-1}\\P(X>1) = 1-0.348678-0.287420\\P(X>1) =0.2639$

The probability is 0.2639 or 26.39%.

b. If p =0.20, what is P(x >1):

$P(X>1) = 1- P(X=0)-P(X=1)\\P(X>1) =1- \frac{10!}{(10-0)!0!}*0.20^0*(1-0.20)^{10-0}- \frac{10!}{(10-1)!1!}*0.20^1*(1-0.20)^{10-1}\\P(X>1) = 1-0.107374-0.268435\\P(X>1) =0.6242$