Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P = 
P = 
P = 0.6364
and
P (value of the stock is between $17 and $21)
P = 
P = 
P = 0.3636
and
Let the upper quartile be Q


(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P = 
P = 
P = 0.5
Answer:
10 Square Inches
Step-by-step explanation:
<u>Trapezoid</u>
Base =12 inches
Height =10 inches
Top side= 10 inches.
Area of a Trapezoid

Area of the Trapezoid=110 Square Inches
<u>Rectangle</u>
Base = 12 inches
Height =10 inches.
Area of a Rectangle=Base X Height
=12 X 10
=120 Square Inches
<u>Difference in Area between the two packages</u>
Difference=Area of Rectangle-Area of Trapezoid
=120-110
=10 Square Inches
Answer:
Step-by-step explanation:
Choose a random fraction less than 1. I will choose 1/4.
1/6 ÷ 1/4 = 1/6 × 4/1 = 4/6 = 2/3
2/3 > 1/6 so this example supports his claim.
Now chose a fraction greater than 1. I will choose 4/3
1/6 ÷ 4/3 = 1/6 * 3/4 = 3/24
3/24 < 1/6 so this contradicts his claim
The expected enrolment in 7 years is 1845.
<h3>What is the expected enrolment?
</h3>
The formula for calculating future value of the number of students is an exponential equation with this form:
FV = P (1 + r) ^n
- FV = Future population
- P = Present population
- R = rate of growth of the population
- N = number of years
1500 x (1.03)^7 = 1845
To learn more about future value, please check: brainly.com/question/18760477
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Answer:0.16625
Step-by-step explanation: