Let Cynthia's age be C, then Abigail's age A
since Abigail is 8 years older, her age A = C+8.
20 years ago Cynthia's she was C-20 and Abigail was A-20=3(C-20)
A-20=3C-60
A=3C-40
but we just said A=C+8
so 3C-40=C+8
2C=48
C=24
A=24+8=32
Cynthia's age is 24 and Abigail's age is 32
Answer:
The correct answer would be C- (UV)2 + (VW)2 = (UW)2, because 81 + 144 = 225
-Thank you
Answer:
f(3) = 6
Step-by-step explanation:
Using the recursive rule and f(1) = 10 , then
f(2) = f(1) - 2 = 10 - 2 = 8
f(3) = f(2) - 2 = 8 - 2 = 6
Answer:
The statistical question should be
"how many minutes do I exercise on each day of the week" and "how many minutes do I exercise each day of the week whilst there is background music"
Step-by-step explanation:
Here we have the non statistical question, how many minutes do I exercise each day
We note that a statistical question is one in which there are are different variety answers, where the distribution and the inclination of the the answers is sought
Therefore, statistically, we should ask, "how many minutes do I exercise on each day of the week" or "how many minutes do I exercise each day of the week whilst there is background music".
The rule for a reflection over the x -axis is (x,y)→(x,−y) .
