3 years ago

A circle whose equation is (x-5)^2 + (y+1)^2=36 has a center,C and a radius, r, of

1 answer:

3 0

Answer: The center is (5,-1) and radius is 6.

Step-by-step explanation: The equation: (x-h)^2+(y-k)^2=r^2 is really important. Since we have 36 equal r^2, square root it to get 6. And the center would be 5, because (x-5) but do the opposite operation, same for y+1.

You might be interested in

What conclusion can be determined from the dot plot below?

EleoNora [17]

Answer:

The number of observations is 15.

3 0

3 years ago

Read 2 more answers

Explain how the value of the 7 in 327,902 will change if you move it to the tens place

rjkz [21]

It will change from having a value of 7,000 to having a value of 70

6 0

3 years ago

The answer are not in the right order first to answer i will name brainly

Nady [450]

Answer:

it would go pink, purple, green

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can someone help me with this question

stira [4]

Answer:

Step-by-step explanation:

this answer is correct , i think if you think of it in logically

3 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers