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3 years ago

How to do this plastic help

Mathematics

1 answer:

liraira [26]3 years ago

4 0

Answer:

39 degrees

Step-by-step explanation:

by seeing the diagram in the attachment, we can see that the angles UWV and VWX are on straight line or, their sum makes 180 degrees.

we also know that sum of the angles in a triangle is 180 degrees.

by using the first statement,

UWV + VWX = 180

UWV + 6x-3 = 180

UWV = 180+3-6x

= 183-6x

by using second statement,

UWV+WVU+VUW=180

substituting the values,

183-6x+2x+5+x+13=180

201-3x=180

substracting 180 from both sides,

21=3x

dividing both the sides by 3,

7=x

the angle VWX=6x-3

substituting 7=x,

VWX=6(7)-3= 39.

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Solve the triangle. Round your answers to the nearest tenth. Law of sines 6 A. M∠C=34 m ∠ C = 34 , b=25 b = 25 , c=16 c = 16 B.

PolarNik [594]

Answer:

$A = 43.0^o$

$B = 55.0^o$

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Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

$\angle C =82^o$

$AB = 29$

$AC = 24$

Required

Solve the triangle

First, we calculate $\angle B$ using sine law:

$\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}$

$\frac{24}{\sin(B)} = \frac{29}{0.9903}$

Cross multiply

$\sin(B) * 29 = 24 * 0.9903$

$\sin(B) * 29 = 23.7672$

Divide both sides by 29

$\sin(B) = 0.8196$

Take arcsin of both sides

$B = \sin^{-1}(0.8196)$

$B = 55.0^o$

Next, calculate $\angle A$ using:

$A + B + C = 180^o$ --- angles in a triangle

$A + 55^o + 82^o = 180^o$

Collect like terms

$A = 180^o-55.0^o - 82^o$

$A = 43.0^o$

Next, calculate BC using sine laws

$\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}$

$\frac{BC}{0.6820} = \frac{29}{0.9903}$

Make BC the subject

$BC = \frac{29*0.6820}{0.9903}$

$BC = 20.0$

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Step-by-step explanation:

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How to do this plastic help​

How to do this plastic help