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anygoal [31]
4 years ago
15

Find 3 solutions to y=1/2x-3

Mathematics
1 answer:
Nady [450]4 years ago
8 0

Answer:

y = (1/2)x - 3

Let's take x = 1, 2, 3. Substitute x into y = (1/2)x - 3 to find out y.

x = 1 => y = (1/2)(1) - 3 = -5/2

x = 2 => y = (1/2)(2) - 3 = -2

x = 3 => y = (1/2)(3) - 3 = -3/2

=> 3 solutions are: (1, -5/2), (2, -2), and (3, -3/2)

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What is the result of factoring out the GCF from the expression (24 + 36)?
Dima020 [189]

24 = 2 · 2 · 2 · 3

36 = 2 · 2 · 3 · 3

GCF(24, 36) = 2 · 2 · 3 = 12

24 = 12 · 2

36 = 12 ·3

24 + 36 = 12 × 2 + 12 × 3 = 12 × (2 + 3)

<h3>Answer: B.</h3>
5 0
3 years ago
Can anyone please tell me what I’m doing wrong. It’s not giving me the full marks. The marks for this question is 4 but I only g
Gekata [30.6K]

Answer:

33%

Step-by-step explanation:

The area of the entire circle:

The radius is 4+3+3 = 10

Area of a circle= pi * r^2


Area of largest circle      = pi * 10^2 = 100 pi


Area of blue ring = Area of blue circle - area of inner white circle

The blue circle has a radius of (4+3) = 7

The inner white circle had a radius of 4

Substituting what we know

Area of blue ring = Area of blue circle - area of inner white circle

                               = pi * r^2 - pi*r^2

                               = pi * 7^2 - pi *4^2

                                = 49pi - 16pi

                                = 33 pi


The percentage of the logo that is blue is the blue ring/ area of largest circle

percentage = 33 pi/100 pi

Canceling pi

percentage = 33/100

                    = 33 %

8 0
3 years ago
What is (f+g)(x)?
Viktor [21]
(f+g)(x)=x^2-36+x^3+2x^2-10

(f+g)(x)=x^3+3x^2-46
6 0
3 years ago
Read 2 more answers
Answer the following.
kakasveta [241]

Answer:

Step-by-step explanation:

1) y=2sin\frac{x}{2} -2

Altitude = 2

Period = 2pi/(1/2) = 4pi

(since 1/2 is coefficient of x)

Altitude interval = [-4,0]

Domain interval = set of all real numbers

Phase shift = 0

Vertical shift = 2 down

2) y=-4sin(2x+pi/2)-2

Altitude = 4

Period = 2pi/(2) = pi

(since 2 is coefficient of x)

Altitude interval = [-6,2]

Domain interval = set of all real numbers

Phase shift = pi/2

Vertical shift = 2 down

8 0
3 years ago
What is the equation to the quadratic function that has zeros at -6 and 16?
ollegr [7]

Answer:

x^2 -10x -96 =0

Step-by-step explanation:

Subtract the zeros from x in factors

(x - -6) (x-16)

(x+6) (x-16)

Set these equal to zero since they are zeros

(x+6) (x-16)  =0

FOIL

x^2 -16x+6x -96 =0

x^2 -10x -96 =0

7 0
3 years ago
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