What is the equation to the quadratic function that has zeros at -6 and 16?
1 answer:
Answer:
x^2 -10x -96 =0
Step-by-step explanation:
Subtract the zeros from x in factors
(x - -6) (x-16)
(x+6) (x-16)
Set these equal to zero since they are zeros
(x+6) (x-16) =0
FOIL
x^2 -16x+6x -96 =0
x^2 -10x -96 =0
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I also worked it out but I got -5/3
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