3.4 m = cm help plezzzzz

I need help on Part B and C on question 2

kap26 [50]

Answer:

The answer to your question is

Part A. Archimedes grades 6 1/4 tests per day

Part B. 8 19/32 days

Part C. 6 26/29 days

Step-by-step explanation:

Part A

Total time = 6 2/5 days

Number of tests = 40 tests

Process

1.- Convert the mixed fraction to improper fraction

6 2/5 = (30 + 2) / 5 = 32/5

2.- Divide 40 by 32/5

40/1 / 32/5 = (40 x 5) / (32 x 1)

= 200 / 32

Simplify

100 / 16 = 50/8 = 25/4

3.- Convert 25/4 to mixed fractions

6

4 25

1

25/4 = 6 1/4

Archimedes grade 6 1/4 tests per day

Part B

15 more tests

Total time = 32/5

Total tests = 40 + 15 = 55

Process

1.- Divide 55 by 32/5

55 / 1 / 32 /5 = (55 x 5) / (32 x 1)

= 275 / 32

2.- Convert 275/32 to a mixed fraction

8

32 275

256

19

Result 8 19/32 days

Part C

1.- Divide 55 by 7.25

50 / 7.25 = 5000 / 725

6

725 5000

- 4350

650

Result 6 650/750 = 6 26/29

3 0

3 years ago

I don't need you to work it out, just theorem(s) i need to reach the answer :)

VikaD [51]

Not sure why such an old question is showing up on my feed...

Anyway, let $x=\tan^{-1}\dfrac43$ and $y=\sin^{-1}\dfrac35$ . Then we want to find the exact value of $\cos(x-y)$ .

Use the angle difference identity:

$\cos(x-y)=\cos x\cos y+\sin x\sin y$

and right away we find $\sin y=\dfrac35$ . By the Pythagorean theorem, we also find $\cos y=\dfrac45$ . (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if $\tan x=\dfrac43$ , then (by Pythagorean theorem) $\sec x=\dfrac53$ , so $\cos x=\dfrac35$ . And from this, $\sin x=\dfrac45$ .

So,

$\cos\left(\tan^{-1}\dfrac43-\sin^{-1}\dfrac35\right)=\dfrac35\cdot\dfrac45+\dfrac45\cdot\dfrac35=\dfrac{24}{25}$

7 0

4 years ago

Jack and Jim sign up with an online music store. Jack chooses 15 downloads for $19.75, and Jim chooses 40 downloads for $43.50.

lina2011 [118]

The answer would be A. The registration fee is $5.50, and the cost per download is $0.95.

Solution
Let x = registration fee
y = cost/downloads

Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50

Thus,
40y + x = 43.50
40y + 19.75 - 15y = 43.50
25y = 23.75
y= 0.95

for x,
x = 19.75 - 15y
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
x = 5.5

3 0

4 years ago

Given: TSR and QRS are right angles; T ≅ Q

allsm [11]

Answer:

The answer is number (2) ⇒ because of the AAS congruence theorem

Step-by-step explanation:

* Lets use the information to solve the problem

- In the given triangles TSR and QRS

# We have a common side RS or SR

# Two right angles TSR and QRS

# m∠T = m∠Q ⇒ given

* So we have two pairs of angles and one common side, lets

revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

* Now lets read the statements and write the missing

Step 1: m∠TSR = m∠QRS = 90° ⇒ because all right angles are congruent

Step 2: m∠T = m∠Q ⇒ because it is given

Step 3: SR ≅ RS ⇒ because of reflexive property (common side)

Step 4: Δ TSR ≅ ΔQRS ⇒ because of the AAS congruence theorem

* The answer is number (2)

4 0

3 years ago

Read 2 more answers

Most investors in the stock market are trying to buy a stock at a _______

gogolik [260]

Answer:

d

Step-by-step explanation:

7 0

3 years ago